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Proof step 6 from proof to-unwind-end (previous step)

⌜n⌝ < ⌜1⌝ + # σ0 ⊦ ⌜a '⌝ + (σ0 to n) = (⌜a '⌝ + (σ0 to (n - 1))) + ⌜(⌜a '⌝ + σ0)[n] '⌝ , ⌜a '⌝ + σ0 = [], n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⌜n⌝ < ⌜1⌝ + # σ0 ⊦ ⌜a '⌝ + σ0 = [], n = 0, σ0 to n = (σ0 to (n - 1)) + ⌜(⌜a '⌝ + σ0)[n] '⌝

Rule argument

Additional information

Used simplifier rules: append-cancel-l: ⊦ ⌜x⌝ + σ0 = ⌜x⌝ + σ1 ↔ σ0 = σ1;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;