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Proof step 2 from proof toinf-to-leq-inf (previous step)

⊦ (⌜nf⌝ to∞ n∞) to m = ⌜nf to m⌝ , n∞ < ⌜m⌝

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: size-inf: ⊦ # ⌜nf⌝ = ∞;%toinf-to-leq: ¬ # σ < n∞ ⊦ ¬ n∞ < ⌜m⌝ → (σ to∞ n∞) to m = σ to m;%to-inf: ⊦ ⌜nf⌝ to n = ⌜nf to n⌝ ;% ⊦ ⌜x⌝ = ⌜x0⌝ ↔ x = x0; (s)% ⊦ ¬ ∞ < n∞; (s)