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Proof step 2 from proof toinftoinf-append-add (
previous step
)
⊦ (σ to∞ n∞) + σ0 to∞ n∞1 + n∞ = (σ to∞ n∞) + (σ0 to∞ n∞1), # σ0 < n∞1, # σ < n∞
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
⊦ (σ to∞ n∞) + σ0 to∞ n∞1 + n∞ = (σ to∞ n∞) + (σ0 to∞ n∞1), # σ < n∞, # σ0 < n∞1
Rule argument
Additional information