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Proof step 108 from proof lim-exists (previous step)

# σσ = ∞, σσ[n0] = σσ[0] + ⌜nf to ii(n0)⌝ , ii(0) = 0, ii(n0 + 1) = ii(n0) + # lf(n0), (nf from ii(n0)) to # lf(n0) = lf(n0), mon(σσ), ∀ m, n. m ≤ n → ii(m) ≤ ii(n), ∀ n. ∃ m. ii(m) ≤ n ∧ n < ii(m + 1) ⊦ σσ[n0] + ⌜lf(n0)⌝ = σσ[0] + ⌜nf to ii(n0 + 1)⌝ , σσ = [], ∃ n. # σσ[n] = ∞

User applied rule insert equation

And obtained the following new goals

Proof step 109:
# σσ = ∞, ii(n0 + 1) = ii(n0) + # lf(n0), ii(0) = 0, (nf from ii(n0)) to # lf(n0) = lf(n0), mon(σσ), ∀ n. ∃ m. ii(m) ≤ n ∧ n < ii(m + 1), ∀ m, n. m ≤ n → ii(m) ≤ ii(n) ⊦ (σσ[0] + ⌜nf to ii(n0)⌝ ) + ⌜lf(n0)⌝ = σσ[0] + ⌜nf to ii(n0 + 1)⌝ , σσ = [], ∃ n. # σσ[n] = ∞

Rule argument

pos: left 2 flags: discard

Proof step 108 from proof lim-exists (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information