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Proof step 110 from proof lim-exists (previous step)

# σσ = ∞, ii(0) = 0, ii(n0 + 1) = ii(n0) + # lf(n0), (nf from ii(n0)) to # lf(n0) = lf(n0), mon(σσ), ∀ m, n. m ≤ n → ii(m) ≤ ii(n), ∀ n. ∃ m. ii(m) ≤ n ∧ n < ii(m + 1) ⊦ # σσ[0] = ∞, (nf to ii(n0)) + lf(n0) = nf to ii(n0 + 1), σσ = [], ∃ n. # σσ[n] = ∞

User applied rule insert equation

And obtained the following new goals

Proof step 111:
# σσ = ∞, ii(n0 + 1) = ii(n0) + #((nf from ii(n0)) to # lf(n0)), ii(0) = 0, mon(σσ), ∀ n. ∃ m. ii(m) ≤ n ∧ n < ii(m + 1), ∀ m, n. m ≤ n → ii(m) ≤ ii(n) ⊦ # σσ[0] = ∞, (nf to ii(n0)) + ((nf from ii(n0)) to # lf(n0)) = nf to ii(n0 + 1), σσ = [], ∃ n. # σσ[n] = ∞

Rule argument

pos: left 4 flags: rotate, discard

Proof step 110 from proof lim-exists (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

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