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Proof step 17 from proof lim-exists (previous step)

# σσ[n] = ∞, # σσ = ∞, n < n0, mon(σσ), σσ[n] ⊑ σσ[n0] ⊦ σσ[n0] = σσ[n], n0 = 0, σσ = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
# σσ = ∞, # σσ[n] = ∞, σσ[n] + σ = σσ[n0], n < n0, mon(σσ) ⊦ σσ[n0] = σσ[n], n0 = 0, σσ = []

Rule argument

Additional information

Used simplifier rules: prefix-def: ⊦ σ ⊑ σ0 ↔ (∃ σ1. σ + σ1 = σ0);