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Proof step 19 from proof lim-exists (previous step)

# σσ[n] = ∞, # σσ = ∞, mon(σσ) ⊦ σσ = [], ∃ n0, σ1. (σσ[n] to m) + σ1 = σσ[n0]

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: n, σσ[n] from m abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ ¬ ∞ < n∞; (s)%¬ # σ < ⌜n⌝ ⊦ (σ to n) + (σ from n) = σ ↔ true; (ss)%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2; from specification stream Used terms: n, σσ[n] from m