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Proof step 8 from proof val-total-01 (previous step)

pos(char, sortedchars) ≤ pos(char2, sortedchars) ⊦ char = char2, pos(char, sortedchars) < pos(char2, sortedchars)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
pos(char, sortedchars) = pos(char2, sortedchars) ⊦ char = char2

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m; (s)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)