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Proof step 5 from proof val-trans-01 (previous step)

char < char2, pos(char2, sortedchars) < pos(char3, sortedchars) ⊦ char < char3

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ char1 < char2 ↔ pos(char1, sortedchars) < pos(char2, sortedchars)
Proof step 7:
pos(char2, sortedchars) < pos(char3, sortedchars), pos(char, sortedchars) < pos(char2, sortedchars) ⊦ char < char3

Rule argument

spec: <toplevel> name: Char-less seq: ⊦ char1 < char2 ↔ pos(char1, sortedchars) < pos(char2, sortedchars) subst: [char2, char1] → [char2, char] flags: <all paths>

Additional information

Used terms: char2, char