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Proof step 17 from proof eq-leninv (previous step)

m +1 = nσ[n], ⌜n⌝ < # nσ, stutf(nσ), ∀ nσ, n. m = nσ[n] ∧ ⌜n⌝ < # nσ ∧ stutf(nσ) → (⌜nσ[n]⌝ = leninv(nσ) ↔ # nσ = ∞ ∧ (∀ m. n < m ∧ ⌜m⌝ < # nσ → nσ[m] = nσ[n])) ∨ nσ[n] = 0 ⊦ ⌜nσ[n]⌝ = leninv(nσ) ↔ # nσ = ∞ ∧ (∀ m. n < m ∧ ⌜m⌝ < # nσ → nσ[m] = nσ[n]), nσ[n] = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
m + 1 = nσ[n], ⌜n⌝ < # nσ, stutf(nσ), ∀ nσ, n. m = nσ[n] ∧ ⌜n⌝ < # nσ ∧ stutf(nσ) → (⌜nσ[n]⌝ = leninv(nσ) ↔ # nσ = ∞ ∧ (∀ m. n < m ∧ ⌜m⌝ < # nσ → nσ[m] = nσ[n])) ∨ nσ[n] = 0 ⊦ ⌜nσ[n]⌝ = leninv(nσ) ↔ # nσ = ∞ ∧ (∀ m. n < m ∧ ⌜m⌝ < # nσ → nσ[m] = nσ[n]), nσ[n] = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)