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Proof step 31 from proof eq-leninv (
previous step
)
# nσ = ∞, nσ[m2] + 1 = nσ[n], n < m0, stutf(nσ), m2 < n → nσ[n] = nσ[n], ∀ m1. m2 < m1 → nσ[m1] = nσ[n] ⊦ nσ[m0] = nσ[n]
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 32
:
# nσ = ∞, nσ[m2] + 1 = nσ[n], n < m0, stutf(nσ), ∀ m1. m2 < m1 → nσ[m1] = nσ[n] ⊦ nσ[m0] = nσ[n]
Rule argument
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