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Proof step 42 from proof eq-leninv (previous step)

# nσ = ⌜n0⌝ , nσ[n0 - 1] + 1 = nσ[n], n < n0, stutf(nσ) ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 43:
# nσ = ⌜n0⌝ , nσ[m] + 1 = nσ[n], n0 = m + 1, n < n0, stutf(nσ) ⊦ n0 = 0

Rule argument

spec: nat name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n0, m]

Additional information

Used simplifier rules: stutf-nonempty: ⊦ stutf(nσ) → (nσ = [] ↔ false);% ⊦ # nσ = ⌜0⌝ ↔ nσ = []; (s)%n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n0, m