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Proof step 57 from proof eq-leninv (previous step)

# nσ = ∞, nσ[m0] + 1 = nσ[n], nσ[m0 + 1] = nσ[n], m0 < n, nσ[m0] < nσ[n], stutf(nσ), ∀ m0. n < m0 → nσ[m0] = nσ[n] ⊦ ∃ m1. nσ[m1] = nσ[m0] ∧ (∀ m2. m1 < m2 → nσ[m2] = nσ[m1] + 1)

User applied rule exists right

And obtained the following new goals

Proof step 58:
# nσ = ∞, nσ[m0] + 1 = nσ[n], nσ[m0 + 1] = nσ[n], nσ[m0] < nσ[n], m0 < n, stutf(nσ), ∀ m0. n < m0 → nσ[m0] = nσ[n] ⊦ nσ[m0] = nσ[m0] ∧ (∀ m2. m0 < m2 → nσ[m2] = nσ[m0] + 1)

Rule argument

pos: right 1 terms: m0 abort: F discard: T computed: T

Additional information

Used terms: m0