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Proof step 170 from proof inv-get-inverse-between (previous step)

# nσ = ⌜m0⌝ + ⌜1⌝ , max∞(λ n0. ¬ m0 < n0 ∧ nσ[n0] = nσ[n1] + 1) = ∞, n1 + m + 1 < ∞.n, nσ[n1] < nσ[m0], stutf(nσ), n1 ≤ m0, ∀ m. ¬ m0 < m ∧ nσ[m] = nσ[n1] → ¬ n1 < m ⊦ nσ[n1 + m + 1] = nσ[n1] + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 171:
⊦ max∞(np) = ∞ ↔ (∀ n. ∃ n0. n < n0 ∧ np(n0)) ∨ (∀ n. ¬ np(n))
Proof step 172:
# nσ = ⌜m0⌝ + ⌜1⌝ , nσ[n1] < nσ[m0], n1 + m + 1 < ∞.n, stutf(nσ), n1 ≤ m0, ∀ m. ¬ m0 < m ∧ nσ[m] = nσ[n1] → ¬ n1 < m, (∀ n. ∃ n0. n < n0 ∧ ¬ m0 < n0 ∧ nσ[n0] = nσ[n1] + 1) ∨ (∀ n. ¬(¬ m0 < n ∧ nσ[n] = nσ[n1] + 1)) ⊦ nσ[n1 + m + 1] = nσ[n1] + 1

Rule argument

spec: <toplevel> name: maxinf-inf seq: ⊦ max∞(np) = ∞ ↔ (∀ n. ∃ n0. n < n0 ∧ np(n0)) ∨ (∀ n. ¬ np(n)) subst: [np] → [λ n0. ¬ m0 < n0 ∧ nσ[n0] = nσ[n1] + 1] flags: <all paths>

Additional information

Used terms: λ n0. ¬ m0 < n0 ∧ nσ[n0] = nσ[n1] + 1