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Proof step 30 from proof inv-get-inverse-between (previous step)

# nσ = ∞, ∞.n + m + 1 < max∞(λ n0. nσ[n0] = nσ[m0] + 1).n, ⌜nσ[m0]⌝ + ⌜1⌝ < leninv(nσ), stutf(nσ), ∀ n0. nσ[n0] ≠ nσ[m0], ∀ m. ∃ m0. m < nσ[m0], ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[∞.n + m + 1] = nσ[m0] + 1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: m0

Additional information

Used terms: m0