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Proof step 98 from proof inv-get-inverse-between (previous step)

# nσ = ∞, nσ[m0] < nσ[m1], ∞.n + m + 1 < max∞(λ n0. nσ[n0] = nσ[m0] + 1).n, stutf(nσ), m0 ≤ m1, ∀ m0. m1 < m0 → nσ[m0] = nσ[m1] + 1, ∀ n0. ∃ n1. n0 < n1 ∧ nσ[n1] = nσ[m0] ⊦ nσ[∞.n + m + 1] = nσ[m0] + 1

User applied rule all left

And obtained the following new goals

Proof step 99:
# nσ = ∞, ∞.n + m + 1 < max∞(λ n0. nσ[n0] = nσ[m0] + 1).n, nσ[m0] < nσ[m1], stutf(nσ), m0 ≤ m1, ∀ m0. m1 < m0 → nσ[m0] = nσ[m1] + 1, ∃ n1. m1 < n1 ∧ nσ[n1] = nσ[m0] ⊦ nσ[∞.n + m + 1] = nσ[m0] + 1

Rule argument

pos: left 7 terms: m1 abort: F discard: T computed: F

Additional information

Used terms: m1