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Proof step 2 from proof inv-get-inverse-succ-inf (
previous step
)
# nσ = ∞, ⌜n⌝ < leninv(nσ), stutf(nσ) ⊦ nσ[inv(nσ)[n] + 1] = n + 1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
# nσ = ∞, ⌜n⌝ < leninv(nσ), stutf(nσ) ⊦ nσ[inv(nσ)[n] + 1] = n + 1
Rule argument
Additional information