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Proof step 55 from proof inv-get-inverse-succ (previous step)

# nσ = ∞, nσ[0] = 0, ⌜nσ[n1]⌝ < leninv(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0], ∀ m. ∃ m0. m < nσ[m0], ∀ m. nσ[m] = nσ[n1] → ¬ n1 < m, ∀ n. nσ[n + 1] = nσ[n] ∨ nσ[n + 1] = nσ[n] + 1 ⊦ nσ[n1 + 1] = nσ[n1], nσ[n1 + 1] = nσ[n1] + 1, nσ = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: n1

Additional information

Used terms: n1