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Proof step 76 from proof inv-get-inverse-succ (previous step)

# nσ = ∞, stutf(nσ), n ≤ nσ[m], stutf(nσ) ∧ ⌜m⌝ < # nσ ∧ n ≤ nσ[m] → (∃ m0. m0 ≤ m ∧ nσ[m0] = n), ∀ n0. nσ[n0] ≠ n, ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ nσ[∞.n + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 77:
# nσ = ∞, stutf(nσ), m0 ≤ m, nσ[m0] ≤ nσ[m], ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1, ∀ n0. nσ[n0] ≠ nσ[m0] ⊦ nσ[∞.n + 1] = nσ[m0] + 1

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜m⌝ < ∞; (s)