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Proof step 88 from proof inv-get-inverse-succ (previous step)

# nσ = ∞, nσ[0] = 0, nσ[m + 1] = nσ[m] + 1, nσ[n1] ≤ nσ[m], ∀ m. nσ[m] = nσ[n1] → ¬ n1 < m, ∀ n. nσ[n + 1] = nσ[n] ∨ nσ[n + 1] = nσ[n] + 1 ⊦ nσ[n1 + 1] = nσ[n1] + 1, nσ = []

User applied rule all left

And obtained the following new goals

Proof step 89:
# nσ = ∞, nσ[m + 1] = nσ[m] + 1, nσ[0] = 0, nσ[n1] ≤ nσ[m], ∀ m. nσ[m] = nσ[n1] → ¬ n1 < m, nσ[n1 + 1] = nσ[n1] ∨ nσ[n1 + 1] = nσ[n1] + 1 ⊦ nσ[n1 + 1] = nσ[n1] + 1, nσ = []

Rule argument

pos: left 6 terms: n1 abort: F discard: T computed: T

Additional information

Used terms: n1