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Proof step 91 from proof inv-get-inverse-succ (previous step)

nσ[(# nσ).n - 1] = n1, ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, stutf(nσ), n ≤ n1 ⊦ # nσ = ∞, nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 92:
⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, stutf(nσ), n ≤ nσ[(# nσ).n - 1] ⊦ # nσ = ∞, nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1

Proof step 91 from proof inv-get-inverse-succ (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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