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Proof step 97 from proof inv-get-inverse-succ (previous step)

# nσ = ⌜m⌝ + ⌜1⌝ , max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = n) = ∞, max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = n).n < m, stutf(nσ), n ≤ nσ[m] ⊦ nσ[max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = n).n + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 98:
# nσ = ⌜m⌝ + ⌜1⌝ , max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = n) = ∞, ∞.n < m, stutf(nσ), n ≤ nσ[m] ⊦ nσ[∞.n + 1] = n + 1

Proof step 97 from proof inv-get-inverse-succ (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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