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Proof step 24 from proof inv-get-inverse (previous step)

# nσ = ∞, nσ[n] = nσ[n0], n0 + 1 < n, m < n, nσ[n0] < nσ[m], n0 < m, n0 < n, stutf(nσ), mon≤(nσ) ∧ m ≤ n0 ∧ ⌜n0⌝ < # nσ → nσ[m] ≤ nσ[n0], ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[∞.n] = nσ[n0], n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
# nσ = ∞, nσ[n] = nσ[n0], n0 < n, n0 < m, nσ[n0] < nσ[m], m < n, n0 + 1 < n, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[∞.n] = nσ[n0], n0 = 0

Rule argument

Additional information

Used simplifier rules: stutf-monle: ⊦ stutf(nσ) → (mon≤(nσ) ↔ true);% ⊦ m < n → (n ≤ m ↔ false); (s)