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Proof step 43 from proof inv-inverts-last (previous step)

# nσ = ⌜n⌝ + ⌜1⌝ , leninv(nσ) = ⌜n1⌝ , max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = nσ[n]) = ⌜n2⌝ , nσ[n] < n1, stutf(nσ) ⊦ max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = nσ[n]) = ∞, n2 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 44:
# nσ = ⌜n⌝ + ⌜1⌝ , leninv(nσ) = ⌜n1⌝ , max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = nσ[n]) = ⌜n2⌝ , nσ[n] < n1, stutf(nσ) ⊦ n2 = n

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜m⌝ ≠ ∞; (s)