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Proof step 7 from proof inv-inverts-last (previous step)

# nσ = ⌜n⌝ + ⌜1⌝ , leninv(nσ) = ∞, stutf(nσ) ⊦ ⌜λ m. max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = m).n⌝ [nσ[n]] = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
# nσ = ⌜n⌝ + ⌜1⌝ , leninv(nσ) = ∞, stutf(nσ) ⊦ max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = nσ[n]).n = n

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜nnf⌝ [n] = nnf(n); (s)