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Proof step 2 from proof inv-inverts-leq (previous step)

⌜n⌝ < # nσ, ⌜nσ[n]⌝ < leninv(nσ), stutf(nσ) ⊦ inv(nσ)[nσ[n]] < n ↔ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
inv(nσ)[nσ[n]] < n, ⌜n⌝ < # nσ, ⌜nσ[n]⌝ < leninv(nσ), stutf(nσ) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic