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Proof step 53 from proof inv-inverts-leq (previous step)

# nσ = ∞, nσ[n1] = nσ[n], nσ[n0] = nσ[n], m + 1 < n1, ∞.n < n, m + 1 < n0, m < n0, stutf(nσ), nσ[n] ≤ nσ[m], nσ[m + 1] ≤ nσ[n], nσ[m + 1] ≤ nσ[m], ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 12 terms: m +1

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)% ⊦ m < n + 1 ↔ ¬ n < m; (s)% ⊦ ¬ n < n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m = n + 1 → ¬ m ≤ n; (s) Used terms: m +1