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Proof step 55 from proof inv-inverts-leq (previous step)

# nσ = ∞, max∞(λ n0. nσ[n0] = nσ[n]) = ⌜n1⌝ , n1 < n, stutf(nσ), nσ[n] ≤ nσ[m], ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ max∞(λ n0. nσ[n0] = nσ[n]) = ∞

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 56:
# nσ = ∞, max∞(λ n0. nσ[n0] = nσ[n]) = ⌜n1⌝ , n1 < n, stutf(nσ), nσ[n] ≤ nσ[m], ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜m⌝ ≠ ∞; (s)