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Proof step 70 from proof inv-inverts-leq (previous step)

# nσ = ⌜m⌝ + ⌜1⌝ , ∞.n < n, ∞.n < m, stutf(nσ), n ≤ m, nσ[n] ≤ nσ[m], (∀ n0. ∃ n1. n0 < n1 ∧ ¬ m < n1 ∧ nσ[n1] = nσ[n]) ∨ (∀ n0. m < n0 ∨ nσ[n0] ≠ nσ[n]) ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 71:
# nσ = ⌜m⌝ + ⌜1⌝ , ∞.n < m, ∞.n < n, stutf(nσ), nσ[n] ≤ nσ[m], n ≤ m, ∀ n0. ∃ n1. n0 < n1 ∧ ¬ m < n1 ∧ nσ[n1] = nσ[n] ⊦
Proof step 72:
# nσ = ⌜m⌝ + ⌜1⌝ , ∞.n < m, ∞.n < n, stutf(nσ), nσ[n] ≤ nσ[m], n ≤ m, ∀ n0. m < n0 ∨ nσ[n0] ≠ nσ[n] ⊦

Rule argument

pos: left 7

Proof step 70 from proof inv-inverts-leq (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information