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Proof step 110 from proof inv-ls-succ (previous step)

nσ[n0] = nσ[n1] + 1, leninv(nσ) = ∞, ⌜n0⌝ < # nσ, ⌜n1⌝ < # nσ, n0 < n1, stutf(nσ), n0 ≤ max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n1]).n, ∀ n0. ∃ n2. n0 < n2 ∧ ⌜n2⌝ < # nσ ∧ nσ[n2] = nσ[n1], ∀ m. ⌜m⌝ < # nσ ∧ nσ[m] = nσ[n0] → ¬ n0 < m ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 111:
⊦ mon≤(nσ) ∧ m ≤ n ∧ ⌜n⌝ < # nσ → nσ[m] ≤ nσ[n]

Rule argument

spec: <toplevel> name: monle-leq seq: ⊦ mon≤(nσ) ∧ m ≤ n ∧ ⌜n⌝ < # nσ → nσ[m] ≤ nσ[n] subst: [nσ, m, n] → [nσ, n0, n1]

Additional information

Used simplifier rules: stutf-monle: ⊦ stutf(nσ) → (mon≤(nσ) ↔ true);% ⊦ m < n → m ≤ n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m = n + 1 → ¬ m ≤ n; (s) Used terms: nσ, n0, n1