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Proof step 11 from proof leninv-inf (previous step)

# nσ = ∞, stutf(nσ) ⊦ (∀ n. ∃ n0. n < n0 ∧ (∃ m. nσ[m] = n0 - 1 ∧ ¬(∀ m0. m < m0 → nσ[m0] = n0 - 1))) ∨ (∀ n. ¬(n ≠ 0 → (∃ m. nσ[m] = n - 1 ∧ ¬(∀ m0. m < m0 → nσ[m0] = n - 1)))) ↔ (∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0])

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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