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Proof step 17 from proof leninv-inf (previous step)

# nσ = ∞, nσ[m0] = m2, n = m2 + 1, m0 < m1, nσ[m] + 1 < n, stutf(nσ) ⊦ nσ[m1] = m2, n = 0, ∃ m0. m < m0 ∧ nσ[m] < nσ[m0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
# nσ = ∞, nσ[m] < nσ[m0], m0 < m1, stutf(nσ) ⊦ nσ[m1] = nσ[m0], ∃ m0. m < m0 ∧ nσ[m] < nσ[m0]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m + n < m + n0 ↔ n < n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + 1 ≠ 0; (s)