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Proof step 60 from proof leninv-inf (previous step)

# nσ = ⌜n1⌝ + ⌜1⌝ , nσ[m] = m0, n = m0 + 1, nσ[n1] + 1 < n, stutf(nσ), m ≤ n1, ∀ n. ∃ n0. n < n0 ∧ (∃ m. ¬ n1 < m ∧ nσ[m] = n0 - 1) ⊦ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 61:
# nσ = ⌜n1⌝ + ⌜1⌝ , nσ[n1] < nσ[m], stutf(nσ), m ≤ n1, ∀ n. ∃ n0. n < n0 ∧ (∃ m. ¬ n1 < m ∧ nσ[m] = n0 - 1) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m + n < m + n0 ↔ n < n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + 1 ≠ 0; (s)