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Proof step 5 from proof leninv-is-len-inv (previous step)

stutf(nσ) ⊦ # (leninv(nσ) = ∞ ⊃ ⌜λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n⌝ ;⌜(λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n⌝ ) = leninv(nσ)

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ # ⌜nnf to n⌝ = ⌜n⌝ ; (s)%n∞ ≠ ∞ ⊦ ⌜n∞.n⌝ = n∞; (s)% ⊦ # ⌜nnf⌝ = ∞; (s)