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Proof step 3 from proof leninv-less (previous step)

leninv(nσ) < n∞ ⊦ ∃ n. leninv(nσ) = ⌜n⌝ ∧ ⌜n⌝ < n∞, leninv(nσ) = ⌜leninv(nσ).n⌝ ∧ ⌜leninv(nσ).n⌝ < n∞

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
n∞ ≠ ∞ ⊦ ⌜n∞.n⌝ = n∞

Rule argument

spec: nat-inf name: fin-inject-embed seq: n∞ ≠ ∞ ⊦ ⌜n∞.n⌝ = n∞ subst: [n∞] → [leninv(nσ)] flags: <all paths>

Additional information

Used simplifier rules: ⊦ ¬ ∞ < n∞; (s) Used terms: leninv(nσ)