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Proof step 100 from proof leninv-succ (previous step)

# nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ), m ≤ m1, (∃ m0. ¬ m1 < m0 ∧ nσ[m0] = nσ[m1]) → ¬ nσ[m] < nσ[m1], ∀ m0. (∃ m2. ¬ m1 < m2 ∧ nσ[m2] = m0 - 1) → ¬ nσ[m] + 1 < m0 ⊦ nσ[m1] = nσ[m]

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 4

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