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Proof step 105 from proof leninv-succ (previous step)

# nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ) ⊦ (∃ m. ¬ m1 < m ∧ nσ[m] = nσ[m1]) ∧ (¬ m1 < m0 ∧ nσ[m0] = m - 1 → ¬ nσ[m1] + 1 < m)

User applied rule case distinction

And obtained the following new goals

Proof step 106:
# nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ) ⊦ ∃ m. ¬ m1 < m ∧ nσ[m] = nσ[m1]
Proof step 107:
# nσ = ⌜m1⌝ + ⌜1⌝ , nσ[m0] = m - 1, nσ[m1] + 1 < m, stutf(nσ) ⊦ m1 < m0

Rule argument

pos: right 1

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