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Proof step 78 from proof leninv-succ (previous step)

# nσ = ∞, stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1, ∀ m1. m < m1 → nσ[m1] = nσ[m] ⊦

User applied rule all left

And obtained the following new goals

Proof step 79:
# nσ = ∞, stutf(nσ), m < m + 1 → nσ[m + 1] = nσ[m], ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Rule argument

pos: left 4 terms: m + 1 abort: F discard: T computed: T

Additional information

Used terms: m + 1