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Proof step 81 from proof leninv-succ (previous step)

# nσ = ∞, nσ[m1] = m0 - 1, nσ[m] + 1 < m0, m1 < m2, stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ nσ[m2] = m0 - 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 82:
# nσ = ∞, nσ[m1] = m0 - 1, nσ[m] + 1 < m0, m1 < m2, stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ nσ[m2] = m0 - 1

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic