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Proof step 83 from proof leninv-succ (previous step)

# nσ = ∞, nσ[m1] = m3, m0 = m3 + 1, m1 < m2, nσ[m] + 1 < m0, stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ nσ[m2] = m3, m0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 84:
# nσ = ∞, nσ[m] < nσ[m1], m1 < m2, stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ nσ[m2] = nσ[m1]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m + n < m + n0 ↔ n < n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + 1 ≠ 0; (s)