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Proof step 86 from proof leninv-succ (previous step)

# nσ = ∞, m1 < m2, nσ[m] < nσ[m1], stutf(nσ), mon≤(nσ) ∧ m1 ≤ m ∧ ⌜m⌝ < # nσ → nσ[m1] ≤ nσ[m], ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ nσ[m2] = nσ[m1]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 87:
# nσ = ∞, m < m2, m < m1, nσ[m] < nσ[m1], m1 < m2, m + 1 < m2, stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ nσ[m2] = nσ[m1]

Rule argument

Additional information

Used simplifier rules: stutf-monle: ⊦ stutf(nσ) → (mon≤(nσ) ↔ true);% ⊦ m +1 = m + 1; (s)% ⊦ m < n → n ≠ 0; (s)%trans: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification nat-basic%lf: ⊦ m < n ∧ n < n0 → m +1 < n0; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ ⌜m⌝ < ∞; (s)% ⊦ m < n → (n ≤ m ↔ false); (s)