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Proof step 98 from proof leninv-succ (previous step)

# nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ), m ≤ m1, ∀ m0. (∃ m2. ¬ m1 < m2 ∧ nσ[m2] = m0 - 1) → ¬ nσ[m] + 1 < m0 ⊦ nσ[m1] = nσ[m]

User applied rule all left

And obtained the following new goals

Proof step 99:
# nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ), m ≤ m1, (∃ m2. ¬ m1 < m2 ∧ nσ[m2] = nσ[m1] + 1 - 1) → ¬ nσ[m] + 1 < nσ[m1] + 1, ∀ m0. (∃ m2. ¬ m1 < m2 ∧ nσ[m2] = m0 - 1) → ¬ nσ[m] + 1 < m0 ⊦ nσ[m1] = nσ[m]

Rule argument

pos: left 4 terms: nσ[m1] + 1 abort: F discard: F computed: F

Additional information

Used terms: nσ[m1] + 1