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Proof step 15 from proof leq-leninv (previous step)

# nσ = ∞, nσ[m] = n1, n1 + 1 < nσ[n], ⌜n⌝ < # nσ, stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
# nσ = ∞, nσ[m] + 1 < nσ[n], stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜m⌝ < ∞; (s)