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Proof step 24 from proof leq-leninv (previous step)

# nσ = ⌜n0⌝ , n0 = m + 1, nσ[m] + 1 < nσ[n], n < n0, stutf(nσ) ⊦ n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
# nσ = ⌜m⌝ + ⌜1⌝ , nσ[m] + 1 < nσ[n], stutf(nσ), n ≤ m ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n + 1 ↔ ¬ n < m; (s)% ⊦ m + 1 ≠ 0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ ⌜m + n⌝ = ⌜m⌝ + ⌜n⌝ ; (s)