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Proof step 5 from proof leq-leninv (previous step)

⌜n⌝ < # nσ, stutf(nσ), ∃ n0. leninv(nσ) = ⌜n0⌝ ∧ ⌜n0⌝ < ⌜nσ[n]⌝ ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
leninv(nσ) = ⌜n0⌝ , n0 < nσ[n], ⌜n⌝ < # nσ, stutf(nσ) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ ⌜m⌝ < ⌜n⌝ ↔ m < n; (s)