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Proof step 10 from proof lsleninv-1 (previous step)

m0 = m1 +1, ⌜m0⌝ = leninv(nσ), m0 < nσ[m], ⌜m⌝ < # nσ, n < nσ[m], stutf(nσ), m0 ≤ n ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⌜m1⌝ + ⌜1⌝ = leninv(nσ), m1 < nσ[m], ⌜m⌝ < # nσ, n < nσ[m], m1 < n, m1 + 1 < nσ[m], stutf(nσ) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%trans: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification nat-basic%lf: ⊦ m < n ∧ n < n0 → m +1 < n0; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m + 1 ≤ n ↔ m < n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ ⌜m + n⌝ = ⌜m⌝ + ⌜n⌝ ; (s)% ⊦ m +1 = m + 1; (s)