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Proof step 19 from proof lsleninv-1 (previous step)

# nσ = ∞, nσ[m2] = m1, nσ[m0] < nσ[m], m1 < nσ[m0], m1 < nσ[m], ⌜m⌝ < # nσ, m1 + 1 < nσ[m], stutf(nσ), m0 ≤ m, ∀ m0. m2 < m0 → nσ[m0] = nσ[m2] + 1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
# nσ = ∞, nσ[m2] < nσ[m], nσ[m0] < nσ[m], nσ[m2] < nσ[m0], nσ[m2] + 1 < nσ[m], stutf(nσ), m0 ≤ m, ∀ m0. m2 < m0 → nσ[m0] = nσ[m2] + 1 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜m⌝ < ∞; (s)% ⊦ m +1 = m + 1; (s)%trans: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification nat-basic%lf: ⊦ m < n ∧ n < n0 → m +1 < n0; (forward) from specification nat-basic