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Proof step 8 from proof maxinf-fin (previous step)

max∞(np) = ∞, np(n), ∀ n. ∃ n0. n < n0 ∧ np(n0), ∀ m. np(m) → ¬ n < m, ∃ n0. n < n0 ∧ np(n0) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
max∞(np) = ∞, n < n0, np(n), np(n0), ∀ n. ∃ n0. n < n0 ∧ np(n0), ∀ m. np(m) → ¬ n < m ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic