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Proof step 2 from proof mon-eq (previous step)

⌜n⌝ < # nσ, ⌜n0⌝ < # nσ, mon<(nσ) ⊦ nσ[n] = nσ[n0] ↔ n = n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information