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Proof step 2 from proof monle-leq (previous step)

⌜n⌝ < # nσ, mon≤(nσ), m ≤ n ⊦ nσ[m] ≤ nσ[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
nσ[n] < nσ[m], ⌜n⌝ < # nσ, mon≤(nσ), m ≤ n ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)